Physics, asked by jai4530, 9 months ago

In a hydraulic
jack the two pistons are of area of cross
section in the ratio 1.4. What force is needed on the
smaller piston to overcome a force of 100N on the bigger
piston.

Answers

Answered by Anonymous

$<html><head><style> body {display: grid; min-height: 100vh; justify-content: center; align-content: center; background: repeating-linear-gradient(circle, white, pink, blue); background: repeating-radial-gradient(circle, white, pink, blue);} @keyframes heart-path {99% {stroke-dashoffset: 0; fill: none;}100% {fill: firebrick;}} </style>$

$<html><head><style> body {display: grid; min-height: 100vh; justify-content: center; align-content: center; background: repeating-linear-gradient(circle, white, pink, blue); background: repeating-radial-gradient(circle, white, pink, blue);} @keyframes heart-path {99% {stroke-dashoffset: 0; fill: none;}100% {fill: firebrick;}} </style>$

$\hugel\green{\boxed{\blue[\boxed{\orange{\boxed{\bf{\mathcal{\purple{ANSWER}}}}}}}}}}$

F1=100N A1=10m2

F2=xN A2=1m2

Since pressure = constant

hence, F1/A1=F2/A2
=100/10=x/1
=x=10N

Previous Question

Next Question

In a hydraulicjack the two pistons are of area of crosssection in the ratio 1.4. What force is needed on thesmaller piston to overcome a force of 100N on the biggerpiston.​

Answers

In a hydraulic
jack the two pistons are of area of cross
section in the ratio 1.4. What force is needed on the
smaller piston to overcome a force of 100N on the bigger
piston.