Question

In a hydraulic lift at a service station, the radii of
the large and small pistons are in the ratio of 20:
1. What weight placed on the small piston will be
sufficient to lift a car of mass 1200 kg.​

Answer 1

Answer:

Pressure is the amount of force acting per unit area. That is, P=F/A.

where:

p is the pressure,

F is the normal force,

A is the area of the surface on contact. Let us consider A = πr

2

.

Therefore,

πr

1

2

F

1

=

πr

2

2

F

2

.

In this case,

20

2

1500

=

1

2

W

,W=3.75kg.

Hence, weight to be placed on the small piston sufficient to lift a car of mass 1500 kg is 3.75 kg.