In a hydraulic lift system, what must the surface area of a piston be in cm² if a pressure of 1300 kPa is used to give a desired upward force of 20000 N?
F1/A1 = F2/A2
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Explanation:
according to Pascal's law
F1/A1= F2/A2. (1)
given pressure P1 =F1/A1=1300kPa = 1300×10^3pa
upward force F2= 20000N
A2=?
using. (1)
1300× 10^3 = 20×10^3/A2
A2= 2/130
A2= 0.01538N/m^2
hope this helps...
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