In a hydraulic lift the diameters of the smaller and larger pistons are 1cm and 3cm respectively. If the smaller piston is pushed in through 6cm, how much does the larger piston move out?
1) 1.67 cm
2) 0.67cm
3) 0.67m
4) 1.67m
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Explanation:
Correct option is A)
As water is considered to be incompressible, so volume covered by inward movement of smaller piston = volume covered by outward movement of larger piston.
L
1
A
1
=L
2
A
2
L
2
=
A
2
A
1
L
1
=
π(D
2
/2)
2
π(D
1
/2)
2
L
1
=(
D
2
D
1
)
2
L
1
=(
3cm
1cm
)
2
×6cm=
9
6
cm=
3
2
cm
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