Physics, asked by Ovel, 19 days ago

In a hydraulic lift, the radii of the pistons are 2.50cm and 10.0cm. A car weighing w = 10.0kN is to be lifted by the force of the large piston. (a) What force (Fa) must be applied to the small piston? (b) When the small piston is pushed in by 10.0cm, how far is the car lifted?(c) Find the mechanical advantage of the lift, which is the ratio w/Fa?​

Answers

Answered by 039harshithav
2

Answer:

In a hydraulic lift, the radii of the pistons are 2.50 cm and 10.0 cm. A car weighing W = 10.0 kN is to be lifted by the force of the large piston, (a) What force Fa must be applied to the small piston? (b) When the small piston is pushed in by 10.0 cm, how far is the car lifted? (c) Find the mechanical advantage of the lift, which is the ratio W/Fa.

Step-by-step solution

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Step 1 of 4

Radius of the smaller piston

Radius of the larger piston

Force of the car (weight)

Explanation:

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