in a hydraulic lift, the radius of the small piston is 5cm and that of the large piston is 15 cm. calculate the force of First, if the mass of the car to be lifted is 1350 kg
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Answer:
According to Pascal's law, Pressure is transmitted equally and undiminished through out the fluid.
P1=P2
F1/A1=F2/A2
F1= (A1/A2 ) F2
=[π(5 x10⁻²m)²/π(15x10⁻²m)² ](1350Nx9.8m/s2)
=1470N
=1.5 x 10³ N
The air pressure that will produce this force
P=F1/A1
=1.5x10³N/π(5x10⁻²)² m
=1.9 x 10⁵ Pa
This is almost the double of atmospheric pressure.
Explanation:
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