In a hydraulic lift the surface area of the input piston is 10 cm square the surface area of the output piston is 3000 cm square a 100 N force applied to the input piston raises the output piston by 1 m calculate the work done
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we know that the work done is given by W= F× S WHERE F = 100 N AND S= 1M SO ANSWER WILL BE 100 J
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F1/A1=F2/A2
F2=F1/A1×A2
=100/10×10 ×3000×10
=30000N
Answer:force in the output piston=30000N
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