Question

in a hydraulic lift there are two pistons of area 5 cm 2 and 50 cm 2 find the magnitude of force required to lift a block of weight 1800n placed on the wider piston . also state the law used to arrive at your answer​

Answer 1

Explanation:

We know that, Pressure=

Area

Force

For Larger Piston, P

l

=

625

1250

=2Ncm

−2

So, Pressure on the smaller piston should be equal to 2Ncm

−2

So, Force on smaller piston X=Pressure×Area=2×5=10N

∴

2

X

=

2

10

=5N