Physics, asked by taslimkauser70151, 5 months ago

In a hydraulic machine a force of 3N is applied on the Piston of area of cross section 12 cm2. What force is obtained on its piston of area of cross section 100 cm2.​

Answers

Answered by ronininsurgent
0

Explanation:

pressure = F1/A1 = F2/A2 (Pascal's law)

3 / 12 = F2/100

F2 = 100/4 = 25 N

Similar questions