Physics, asked by taslimkauser70151, 6 months ago

In a hydraulic machine a force of 3N is applied on the Piston of area of cross section 12 cm2. What force is obtained on its piston of area of cross section 100 cm2.

Answers

Answered by ronininsurgent

0

Explanation:

pressure = F1/A1 = F2/A2 (Pascal's law)

3 / 12 = F2/100

F2 = 100/4 = 25 N

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