Question

In a hydraulic machine, the area of the small piston is 50 cm^2 and that of the large piston is 5 m^2. If an effort of 20 N is applied on the small piston, how much load can be lifted on the large piston? Calculate.

*I want the Process of this and the answer is down below me.*

[Answer: 2 × 10^4 N] ​

*Please don't write whatever you want JUST TO GET SOME POINTS*​

Answer 1

Answer:

Correct option is

A

200N

Using   A1F1=A2F2

: 2 × 10^4 N

∴   0.0520=0.5F2            ⟹F2=200  N