Question

 In a hydraulic machine the force exerted by the larger piston is 1250 N. If the diameter of the pistons are 5cm and 25 cm calculated the force exerted on the smaller piston.​

Answer 1

Answer:

sorry I don't know hope

my answer correct

Answer 2

Explanation:

We know that Pressure on both the Piston should be same,

∴Pressure on smaller Piston=Pressure on larger Piston

Area of smaller

Force on smaller

=

Area of larger

Force on larger

∴ Force on Larger=

Area of smaller

Force on smaller

×Area of larger

⇒

2.5×2.5×3.14

50

×12.5×12.5×3.14=1250kgf