Question

In a hydraulic machine, the two pistons are of area of cross section in the ratio 1 : 15. What force is needed on the narrow piston to overcome a force of 150 N on the wider piston

plz answer​

Answer 1

Answer:

Explanation:

A:a = 1:15

f = 150 N

F = ?

In hydraulic Machine

F:f = a: A

F = 15*150

F = 2250 N