Question

In a hydraulic machine, the two pistons are of area of cross section in the ration 1:20. What

force is needed on the narrow piston to overcome a force of 100 N on the wider piston? ​

Answer 1

Answer:

yes it should need ..aka

Answer 2

Explanation:

Correct option is

A

10

F

1

=100NA

1

=10m

2

F

2

=xNA

2

=1m

2

Since pressure = constant

hence,

A

1

F

1

=

A

2

F

2

⇒

10

100

=

1

x

x=10N