Question

In a hydraulic machine two pistons have area of cross-section are in the ratio 1: 15, what force is needed on
the narrow piston to overcome a force of 150 N on the wider piston?
(A) 20 N
(B) 10 N
(C) 40 N
(D) 30 N​

Answer 1

Answer:

(B) 10N is the correct answer ☑

Explanation :

=> 1/15 = x/150

=> x = 150/15

=> x = 10 N ans.

Answer 2

$\huge\boxed{\fcolorbox{black}{pink} {Answer}}$

Ratio = 1 :15

Force exerted on the smaller piston = x

Force exerted on the larger piston = 150 N

Using Unitary Method,

$\frac{1}{15} = \frac{x}{150N} \\ = x = \frac{150N}{15} \\ = x = 10N$

Therefore Option B is correct ✔️