Question

In a hydraulic press, a force of 200N is applied to master piston of area 25cm-2 if the press is designed to produce a force of 5000N,determine;
a)the area of the slave piston
b)the radius of the slave piston

Answer 1

Answer:

625 $cm^{2}$

Explanation:

This question is based on pascal's Law.

So By Pascal's Law

 $\frac{f_{1} }{f_{2} }$ = $\frac{a_{1} }{a_{2} }$

therefore $f_{1}$ =force on input piston =200N

                  $f_{2}$ = Force on output piston = 5000N

therefore after putting the values we get,

a) $a_{2}$ = (25x 5000)/200

     = 625 $cm^{2}$

b) area of the salve piston = $\pi r^{2}$ = 625

so $r^{2}$ = 625/3.14 = 199

so     r =  $\sqrt{199\\}$  = 14.10 cm

Answer 2

Answer:

625cm²

Explanation:

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