Question

in a hydraulic press the diameter of larger and smaller piston are 50 cm and 5cm respectively what is the force exerted on smaller piston​

Answer 1

Explanation:

We know that the pressure on both the piston should be same.

Pressureonsmallerpiston=Pressureonlargerpiston

That is,

Areaofsmaller

Forceonsmaller

=

Areaoflarger

Forceonlarger

Therefore,

Forceonlarger=

Areaofsmaller

Forceonsmaller

×Areaoflarger

⟹

2.5×2.5×3.14

50

×12.5×12.5×3.14=1250kgf

here is your answer

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