Physics, asked by labib09abdullah, 6 days ago

In a hydraulic press the force is 50 N on a piston of area 4 cm².

a)Calculate the pressure in the liquid.

b) Calculate the force on the other piston of area 8 cm².​

Answers

Answered by Anonymous
0

(4 \sqrt{3})^{2}  - (2 \sqrt{2})^{2}  \\  = (4  \times 4\times 3) -( 2  \times 2\times 2) \\  = 48 - 8 = 40

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