in a hydro electric power , 1000×10power3kg water falls through a height of 51m in one second. calculate (1) work done by the following water and (2) power generated under ideal conditions
Answers
Answered by
20
Answer:
Given:
Mass of water = 1000 × 10³ kg
Height through which it falls = 51 metres
Time taken = 1 second
To find:
- Work done by water
- Power generated under ideal conditions
Concept:
For calculation of work done , we can easily understand that the whole Potential energy of the water at that height will be converted to work done while falling.
This is because gravitational force is an conservative force.
And finally power can be calculated as the rate of work done .
Calculation:
This whole PE will be converted to work done by water.
Now , Calculation of power :
Answered by
43
Given :
- Mass (m) = 1000 × 10³ kg
- Height (h) = 51 m
- Time (t) = 1 s
Solution :
As, we know that. Work Done = Potential Energy by Work Energy Theorem
So,
And formula for Power is :
__________________________________
Additional Information :
Power :
- Power is defined as rate of Work done.
- Power = Work Done /Time
- Power is measures in Watt (W)
- Power is Scaler Quantity
Work Done :
- It is defined as When a force is applied to change distance of object is Work done.
- Work Done = F*s
- Measured in Joules (J)
- It is a scaler quantity
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