Question

In a hydroelectric power station 1000 kg water is allowed to drop through a height of 100m in 1 second.If the conversion of potential energy to electrical energy is 60% calculate the power output.g=10m/s^2
Ans.. 6*10^5W​

Answer 1

Answer:

P = 60/100 x mgh/t

= 6/10 x 1000×10×100/1

=6×10^5 W

Answer 2

I hope this will help you