Question

In a hydrogen atom, an electron of mass m and charge e revolves in an orbit of radius r making n revolutions per second. If the mass of hydrogen nucleus is m, the magnetic moment associated with the orbital motion of electron is

Answer 1

Answer:

πner⅔ if it is helpful please follow me

Answer 2

Magnetic moment associated with the orbital motion of electron = π ner²

Mass of electron= m

The revolving electron will be equivalent to the current , so

I= e/T,

e- charge of the electron

T- time period of revolution

T = 2π/w

=> T = 2π/2πn [ w = 2πn , Given that the electron makes n revolutions per second ]

=> T = 1/n

Therefore ,

I = e×n

The magnetic moment will be equal to the product of the current flowing and the area -

μ = I ×A,

I - current

A - area of the orbital

A= π r² , I = e×n

μ = Magnetic moment = (en)×πr²

= π ner²