Question

In a hydrogen atom,if energy of an electron in ground state is -13.6eV,then that in the 2nd excited state is :

Answer 1

E = E° /n²

E = -13.6 / n² eV

''''n = 3 for 2nd exited state

E = -13.6/ 3² eV

E = -13.6/9 eV

= -1.51 eV