Question

In a hydrogen atom, the electron revolves round the
proton in a circular orbit of radius 0.528 A with a
speed of 2.18 x 10^6m/s. Calculate the centripetal
force acting on the electron. (Mass of electron=9.1*10^-31,A=10^-10m)
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Answer 1

Answer:

41x10∧-9 N

Explanation:

the centripetal  force acting on the electron F = mv²/2R

F = mv²/2R = 9.1*10^-31(  2.18 x 10^6  )²/2x0.528x10∧-10 = 41x10∧-9 N