Question

In a hydrogen atom, when an electron is revolving in a circular orbit of radius 0.53A power degree around the nucleus,it is found that it makes 6.64×10 to the power 15 rev/s.its angular speed is

Answer 1

Explanation:

Data:

radius = r = 0.53 * 10^-10 m

The electron revolving with = 6.6 * 10^-15 radiation/s

Required:

magnetic field = B = ?

Calculation:

we know that

      B = k 2 π (Qv)/r

where  k is constant and its value is "10^-7"

Putting values we get

       B = (10^-7) . 2 (3.14)*(1.6*10^-19)*(1.6*10^15) / (0.53*10^-10)

⇒    B=12.5 Wb/(m^2)

So The answer is "12.5Wb/(m^2) "