Physics, asked by atluri1930, 7 months ago

In a hydrogen atom, when an electron is revolving in a circular orbit of radius 0.53Aº around the nucleus
it is found that it makes 6.64 x 10 rev/s. Its angular speed is
a) 4. 17 x 1016 rads! b) 8 x 1015 rads!
c) 10 % radis
d) 5 x 10 rads​

Answers

Answered by athpatil
2

Answer:Given :  ν=6.6×1015 rev/s       R=0.53 A

Current flowing  I=eν

∴  I=1.6×10−19×6.6×1015

⟹  I=10.56×10−4 A

Magnetic field at the center of orbit  Bc​=2Rμo​I​

∴ Bc​=2×0.53×10−104π×10−7×10.56×10−4​

⟹  Bc​=12Wb/m

Explanation:

Similar questions