In a hydrogen atom, when an electron is revolving in a circular orbit of radius 0.53Aº around the nucleus
it is found that it makes 6.64 x 10 rev/s. Its angular speed is
a) 4. 17 x 1016 rads! b) 8 x 1015 rads!
c) 10 % radis
d) 5 x 10 rads
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Answer:Given : ν=6.6×1015 rev/s R=0.53 A
Current flowing I=eν
∴ I=1.6×10−19×6.6×1015
⟹ I=10.56×10−4 A
Magnetic field at the center of orbit Bc=2RμoI
∴ Bc=2×0.53×10−104π×10−7×10.56×10−4
⟹ Bc=12Wb/m
Explanation:
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