Question

in a hydrogen-like hypothetical atom ionization energy is 12 ev first excitation energy for such an atom is

Answer 1

Answer: Answer to the question is 3ev/atom.

Explanation:

Answer 2

Answer:

First excitation energy for a hydrogen-like hypothetical atom is equal to 9eV.

Explanation:

The ionization energy  of H-atom  $E_{1}=13.6 \frac{z^{2}}{n^{2}}eV=13.6z^{2}= 12eV$

We know that

               $\delta E= E_{1}-E_{2}=13.6z^{2}(\frac{1}{n_{1}^{2}}- \frac{1}{n_{2}^{2}})$

$n_{1}=1$ and $n_{2}=2$

First excitation energy :

               $\delta E=13.6z^{2}(\frac{1}{1}- \frac{1}{4})=13.6z^{2}(\frac{3}{4})\\ \\ \delta E=12eV (\frac{3}{4})\\ \\ \delta E= 9eV$

Therefore the 1st excitation energy equals to 9eV.