Question

In a hydrogen like sample, all the electrons are in a particular excited state. When electrons make transition up to ground state, then 6 different types of photons are observed. If second excitation potential of the sample is 193.64 V, then identify the sample.

Also please give the explanation.​

Answer 1

Answer:

We know that E=13.6×n2z2

                        13.6=13.6×4222

                                 z=4 

∴  Species is Berellium E  (for n=3) $$13.6\times \dfrac{4^{2}}{3^{2}}= 24.177\simeq 25$$

 ∴25eV photon can set free electron from 2nd excited state.

Answer 2

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