In a hydrogen tube it is observed that through a
given cross-section 3.13 x 10 electrons persec
moving from right to left and 3.12 x 10) protons
per sec are moving from left to right. The electric
current in the discharge tube and its direction is
1) 1.6uA towards left 2) 1.6uA towards right
3) 1 mA towards left 4 )1 mA towards right
Answers
Answer:
option4 1mAtowars right
Explanation:
Here, number of electrons n
e
=3.31×10
15
and number of protons n
p
=3.12×10
15
As both the charge carriers are moving opposite to each other thus the current due to each carrier will add up.
Current due to both the charge carriers is in right direction.
Current I=n
e
q
e
+n
p
q
p
=3.31×10
15
×1.6×10
−19
+3.12×10
15
×1.6×10
−19
=1.03×10
−3
≈1mA towards right.
Answer:
Here, number of electrons n
e
=3.31×10
15
and number of protons n
p
=3.12×10
15
As both the charge carriers are moving opposite to each other thus the current due to each carrier will add up.
Current due to both the charge carriers is in right direction.
Current I=n
e
q
e
+n
p
q
p
=3.31×10
15
×1.6×10
−19
+3.12×10
15
×1.6×10
−19
=1.03×10
−3
≈1mA towards right.
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