In a hydrolic jack as shown mass of the car w=800kg a=10 cm2 and a2=10 m2 the minimum force required to lift the car is
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2
F1/a1=F2/a2
F1=800*9.8*10/100000
F1=0.784N
Answered by
1
Given
Mass=800kg
a=10 cm/s2
=0.1m/s^2
Therefore force with produces downward = m×a
=80N
Force the jack has to conquer = 80N
This is the min. force required to lift the car.
Mass=800kg
a=10 cm/s2
=0.1m/s^2
Therefore force with produces downward = m×a
=80N
Force the jack has to conquer = 80N
This is the min. force required to lift the car.
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