In a hydrolysis reaction, 5 gram ethyl acetate is hydrolysed in the presence of dilute hcl in 300 minutes. If the reaction is of first order and initial concentration of ethyl acetate is 22g/litre. Calculate the rate constant of the reaction
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Hello! dear,
Your answer goes like this ....
Solution:-----
K=2.303/t log {R}0/{R}
We know that here t = 300 minutes
{R}0 =22 grams L^-1
{R}={22-5}gL^-1 =17 L^-1
By substituting these values in the Equation,We get:--
K=2.303/300 minutes x0.112 minute^-1
⇒8.597x10^-4 minute^-1.
Thank you dear,
Hope It helps.
Your answer goes like this ....
Solution:-----
K=2.303/t log {R}0/{R}
We know that here t = 300 minutes
{R}0 =22 grams L^-1
{R}={22-5}gL^-1 =17 L^-1
By substituting these values in the Equation,We get:--
K=2.303/300 minutes x0.112 minute^-1
⇒8.597x10^-4 minute^-1.
Thank you dear,
Hope It helps.
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