Math, asked by fahimphotography1234, 7 months ago

In a Internee program at Airline Company, 60 percent of the internees are female and 40 percent male. 80 percent of the females are business students, and 65 percent of the males are business students. a) An internee is selected at random. What is the probability that the person selected is a female who is not a business student? b) Are gender and field of study, independent in this case? Why?

Answers

Answered by nidaeamann
1

Answer:

3/25

Step-by-step explanation:

Now here there are two conditions, that the intrenee selected should be a woman and she should not be a bussiness student.

Probability of woman intern = 60 / 100 = 6 /10

Now the other condition is that this woman  she should not be a bussiness student.  

That probability would be = 20/100

Probability that selected intern be a non bussiness student woman = 6 / 10 x 2 / 10 = 12 / 100

Probability that selected intern be a non bussiness student woman  = 3/25

Answered by amitnrw
2

Given :  60 percent of the internees are female and 40 percent male. 80 percent of the females are business students, and 65 percent of the males are business students

To find : person selected is a female who is not a business student

Are gender and field of study, independent in this case

Solution:

Let say Total internee  = 100A

Female = 60A

Male  = 40A

Business Studies Female = (80/100)60A = 48A

Female not Business Studies = 60A - 48A = 12A

Business Studies Male = (65/100)40A = 26A

Total Business Studies = 48A + 26A = 74A

Probability that the person selected is a female who is not a business student = 12A/100A  =  3/25

Probability Of Selecting Female = 60A/100A  = 3/5

Probability Of Selecting Female  if Business Studies =  48A/74A  = 24/37

3/5  ≠ 24/37

Not independent

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