In a isosceles triangle each of its base angle is 30 degree less than its remaining angles.Find the angles of triangke
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Here is your answer
Let the three angles be a, b and c.
b and c are base angles.
angle b = angle C = angle a - 30°
Let angle a be 'x'.
x+x-30+x-30=180 (sum of angles of triangle is 180°,anglesum property of triangle)
3x-60=180
3x=180+60
x=240/3=80
Therfore,
Angle a = 80°
Angle b = 50°
Angle c = 50°
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