In a isosceles triangle, if the vertex angle is twice the sum of the base angles, calculate the angles of the triangle
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Let bas angles be A, B
Than vertex angle be 2(A+B)
In triangle ABC
A+B+2(A+B)=180
(A+B)+2(A+B)=180
3(A+B)=180
A+B=180/3
A+B=60............ (1)
but triangle ABC is a isoscleles triangle so
Angle A=angle B......... (2)
From (1)&(2)
A+B=60
A+A=60
2A=60
A=30=B
Than vertex angle be 2(A+B)
In triangle ABC
A+B+2(A+B)=180
(A+B)+2(A+B)=180
3(A+B)=180
A+B=180/3
A+B=60............ (1)
but triangle ABC is a isoscleles triangle so
Angle A=angle B......... (2)
From (1)&(2)
A+B=60
A+A=60
2A=60
A=30=B
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