In a isosceles triangle , prove that the altitude from the vertex bisects the base.
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Answered by
172
Hi
Here is a solution to your answer
Hope it helps
Here is a solution to your answer
Hope it helps
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Answered by
117
Step-by-step explanation:
let us take a triangle ABC and draw an altitude AD
being an isosceles triangle
in tri ACD and tri CDB
CD =CD (common )
CA = CB ( equal opposite sides)
angle A = angle B ( angle opposite to opposite sides are also equal )
therefore : tri ACD and CDB are congruent by ASA rule
so , AD = DB by CPCT
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