Question

in a isosceles triangle the leangth of equal sides each exceed that of the base by 5 cm the perimeter of the triangle is 43cm find the leangth of sides of triangle ​

Answer 1

Answer:

11 , 16 and 16 cm

Step-by-step explanation:

let the base be x cm

then the equal sides are (x+5) cm each

as per the question,

$= > x + 5 + x + 5 + x = 43 \\ = > 3x + 10 = 43 \\ = > 3x = 33 \\ = > x = 11$

sides of the triangle are

side1 = x + 5 = 11 + 5 = 16 cm

side2 = x + 5 = 11 + 5 = 16 cm

side3 = x = 11 cm

Answer 2

Answer: length of each equal sides = 16 cm

               Length of the base              = 11cm

Step-by-step explanation:

Let the equal sides be ‘x’ and ‘x’

so the base =  x-5  (since the equal sides exceed the base by 5)

Perimeter = Sum of all sides = 43

                = x + x + x - 5

                = 3x - 5

                 

So,  = 3x - 5 = 43

      = 3x       = 43 + 5

      = 3x       = 48

      = x         = 48 / 3 = 16

Each of the equal sides of the triangle = x = 16cm

Base of the triangle                                = x - 5 = 16 - 5

                                                                 = 11 cm