In a journey of 300 km a train slowed down speed by 50 km/hr due to bad weather and took one hour more to complete the journey the original speed of the train is
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Answer:
the original speed of the train is 150 kmph
Step-by-step explanation:
Let the original speed of the train = s
Let the original time taken be t
Distance = speed x time
=> 300 = st
When the speed is reduced by 50 kmph, new speed = s-50
New time = t + 1
Hence,
(s-50)(t+1) = 300
=> st +s -50t -50 =300
=> 300 + s -50t -50 =300
=> s - 15000/s - 50 = 0
=> s^2 -50s -15000 =0
Solving the above quadratic eqn we get
s = 150 kmph
Hence the original speed of the train is 150 kmph
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