In a journey of 80km, a train covers the first 60 km at 40km/h and the remaining at 20km/h. How would one calculate the average speed of the whole journey?
Answers
Answered by
52
Hey mate your answer goes like this
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First let us write the given data.
Total distance to cover = 80km.
Distance covered with speed 40 km/h = 60 km
Distance covered with speed 20 km/h = 20 km (80–60=20)
Formulae used :
Speed= distance /time, time = distance /speed
Average speed = total distance /total time
Solution :
Time required to cover first 60 km with speed 40km/h=60/40=1.5 hours
Time required to cover remaining distance with speed 20km/h=20/20=1 hour
Total time of journey = 2.5 hours
Average speed = 80/2.5= 32 km/h
HOPE IT HELPS!!
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sidhant41:
hello
Answered by
13
hey bro here is ur answer
TOTAL DISTANCE = 80 KM ..
for first 60 km ....it's speed is 40 km/h
it means that time = distance /speed
so time for 1st 60 km is .. 60/40 =3/2 hrs.
next remaining distance = 80-60 = 20
speed = 20 km/h so time = 20/20= 1 hr.
TOTAL TIME = 3/2+1 = (3+2)/2 = 5/2 HRS..
total distance = 80km ..
so avg. speed = total distance / total time
= 80/(5/2) = 80×2)/5 = 16×2 = 32 km/h
hope it's help u❤️❤️❤️
TOTAL DISTANCE = 80 KM ..
for first 60 km ....it's speed is 40 km/h
it means that time = distance /speed
so time for 1st 60 km is .. 60/40 =3/2 hrs.
next remaining distance = 80-60 = 20
speed = 20 km/h so time = 20/20= 1 hr.
TOTAL TIME = 3/2+1 = (3+2)/2 = 5/2 HRS..
total distance = 80km ..
so avg. speed = total distance / total time
= 80/(5/2) = 80×2)/5 = 16×2 = 32 km/h
hope it's help u❤️❤️❤️
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