Question

In a juice, guava is 85% and rest is sugar. In another juice, pomegranate is 90% while rest is sugar. Both the
juices are mixed in the ratio of 3:2. Find concentration of sugar in final mixture. (in %)
1.10
2.11
3.12
4.13
5. 14
​

Answer 1

Answer:

Juice 1 17:3

Juice 2 9:1

or 18:2

17:3*3

18:2*2

it becomes 51:9

36:4

total prcentage =100

ie sugar=13%[9+4]

Step-by-step explanation:

Answer 2

Option 4 : The concentration of sugar is 13% in the final mixture of the two juices in the given ratio.

Given :

Juice 1 contents: 85% Guava, rest is sugar

Juice 2 contents: 90% Pomegranate, the rest is sugar

Ratio of juice in mixture = 3 : 2

To Find :

The concentration of sugar in the mixture

Solution :

Firstly we need to find the content of sugar or its percentage in the two mixtures independently.

Sugar content in Juice 1 = 100% - Guava content

                                         $= 100 - 85 %$

                                         $= 15$%

Sugar content in Juice 2 = 100% - Pomogranate content

                                         $= 100 - 90 %$

                                         $= 10$%

It is given that the two juices are mixed in a ratio of 3:2. So, we find the percentage content of each juice in the mixture.

% Juice 1 in mixture = 3/5 = 60%

% Juice 2 in mixture = 2/5 = 40%

So, the total sugar content in the mixture is the sum of the corresponding percentage content in each of the two juices i.e.

                     = Sugar in 60% of Juice1 + Sugar in 40% of Juice 2

                     = ( 15 % of 60% in Juice 1 ) + ( 10% of 40% in Juice 2 )

                     $= (15*60/100) + (10*40/100)$

                     $= (900/100) + (400/100)$

                     $=9+4$

                     $= 13$

Hence, sugar constitutes 13% of the final mixture.

 

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