Question

in a kilometer race , A gives B a head start 50m & still beats B by 8 m. by what distance A will beat B, if B gives a start of 50 m to A?​

Answer 1

50 m head start beaten by 8 m

and then b gave 50 m head start to A

so

50+8= 58 m ( a beat b )

not sure it's correct

Answer 2

Answer:

From the question A gives B a 50m start explains for B to be 50m ahead of A. If A gives B a 5s start is understood to be B starts 5s ahead of A. Taking the above explanations to consideration,assuming the total time of travel for A to be t the distance covered by A is 1000m and that by B is 950m. So time taken by A being t.That by B is (t–5), so its speed is {950/(t–5)}. When A gives B a 5s start=> B to start before 5s=> his time of travel=(t+5) & distance covered is 950×{(t+5)/(t-5)} which is less by 30m from 1Km=970m.. So 950×{(t+5)/(t-5)}=970=> (t+5)/(t-5)=970/950 => (t+5)/(t-5)=97/95=> 95t+475=97t-485=> 2t=(475+485)=960 or t=480s or 8min. Ans..