In a kilometer race, Rakesh beats Sameer by
200 m. In the same race, Sameer beats Tarun by
200 m. By what distance (in m) does Rakesh beat
Tarun?
Answers
Answer:
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Answer:
Answer: D) 6m
Step-by-step explanation:
A : B = 100 : 90.
A : B = 100 : 90.
A : B = 100 : 90. A : C = 100 : 87.
A : B = 100 : 90. A : C = 100 : 87.
A : B = 100 : 90. A : C = 100 : 87. B/C = (B/A*A/C) = (90/100*100/87) = 30/29
A : B = 100 : 90. A : C = 100 : 87. B/C = (B/A*A/C) = (90/100*100/87) = 30/29
A : B = 100 : 90. A : C = 100 : 87. B/C = (B/A*A/C) = (90/100*100/87) = 30/29 When B runs 30 m, C runs 29 m.
A : B = 100 : 90. A : C = 100 : 87. B/C = (B/A*A/C) = (90/100*100/87) = 30/29 When B runs 30 m, C runs 29 m.
A : B = 100 : 90. A : C = 100 : 87. B/C = (B/A*A/C) = (90/100*100/87) = 30/29 When B runs 30 m, C runs 29 m. When B runs 180 m, C runs (29/30*180)m =174m
A : B = 100 : 90. A : C = 100 : 87. B/C = (B/A*A/C) = (90/100*100/87) = 30/29 When B runs 30 m, C runs 29 m. When B runs 180 m, C runs (29/30*180)m =174m
A : B = 100 : 90. A : C = 100 : 87. B/C = (B/A*A/C) = (90/100*100/87) = 30/29 When B runs 30 m, C runs 29 m. When B runs 180 m, C runs (29/30*180)m =174m B beats C by (180 - 174) m = 6 m.