Math, asked by S712471, 4 months ago

In a lab, a substance was cooled by 28c over a period of 7 hours at a constant rate. What was the change in temperature each hour?

Answers

Answered by nooblygeek
1

Answer:

4 degrees celsius per hour

Step-by-step explanation:

As we know the rate of change is constant then we can find the

rate of change by simply dividing the total change in temperature by the

time elapsed. Hence, \frac{\Delta T}{\Delta t} = \frac{28}{7} = 4 celsius per hour.

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