Question

in a laboratory the count of a bacteria grows by 15%in the first hour , decreases by10%in the second hour and again increases by 8%in the third hour. if the count of bacteria initially was 1225000,what will be the count of bacteria after 3 hours

Answer 1

hope it may help you

Answer 2

There will be 1095903 bacteria after 3 hours.

Step-by-step explanation:

Since we have given that

Increase in the first hour = 15%

Decrease in the second hour = 105

Increase in the third hour = 8%

Initial count of bacteria = 1225000

According to question, we get that

$1225000=P(1+\dfrac{15}{100})(1-\dfrac{10}{100})(1+\dfrac{8}{100})\\\\1225000=P(1+0.15)(1-0.1)(1+0.08)\\\\1225000=P(1.15)(0.9)(1.08)\\\\\dfrac{1225000}{1.15\times 0.9\times 1.08}=P\\\\P=1095902.6\approx 1095903$

Hence, there will be 1095903 bacteria after 3 hours.

# learn more:

In a laboratory count of bacteria grows by 15percent in first hour,decreases by 10 percent in second hour and again decrease by 8 percent in third hour.If count of bacteria initially was 122500,what will be count of bacteria after three hours.

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