In a laboratory, The Count of bacteria in a certain experiment was increasing at the rate of 2.5 % per hour .find the bacteria at the end of 2 hours if the count was initially 506000.
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Answer:
We have, P
0
= Original count of bacteria =506000,
Rate of increase =R=2.5% per hour,
Time =2 hours
∴ Bacteria count after 2 hours = P
P=P
0
(1+
100
R
)
T
=506000×(1+
100
2.5
)
2
=506000×
100
102.5
×
100
102.5
=531616.25=531616 (approx)
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