Question

In a Laboratory, the count of bacteria in a certain experiment was increasing at the
rate of 2.5% per hour. Find the bacteria at the end of 2 hours if the count was initially
5,06,000.​

Answer 1

Answer:

531,616.25

Step-by-step explanation:

This question is based on the formula of Compound Interest

If the population growth is constant for all the given number of time, then

Population after n period of time = P × (1 + R/100)^n

Here the growth is constant so we will use this formula :-

P = 5,06,000

R = 2.5 = 25/10

T = 2 hours

P × (1 + R/100)^n =

5,06,000 × (1 + 25/(10×100))²

5,06,000 × (1 + 25/1000)²

5,06,000 × (1025/1000)²

5,06,000 × 1025/1000 × 1025/1000

506 × 1025 × 1025/1000

518,650 × 1025/1000

51,865 × 1025/100

51,865 × 41/4

51,865 × 10.25

531,616.25

Hence, the number of bacteria at the end of 2 hours will be 531,616.25

Hope it helps

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