In a laboratory, the count of bacteria in a certain experiment was increasing at the rate of 5% per hour. Find the bacteria at the end of 2 hours if the count was Initially 5,06,000
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Answer:
The answer to this question is 557865.
Step-by-step explanation:
This question can be solved using the compound interest formula.
So According to this question,
P =506000
R = 5%
T = 2 hours
Now put in the compound interest formula,
A = P ( 1 + R/100)T
A = 506000 ( 1 + 5/100)2
A = 557865
The answer to this question is 557865.
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