Question

In a laboratory, the count of bacteria in a certain experiment increased at the rate of 2.5% per hour.Find the count of bacteria at the end of 2 hour if it was 5,06,000 in the beginning.
(Please answer as fast as possible)
Please don't sent unwanted answers

Answer 1

for the first hour2.5%= 5,06,000
for the second hour 2.5%=5,06,000

I think ans is 5%=10,12,000

Answer 2

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Here is your answer

Bacteria in the beginning is 506000

Increase by 2.5% per hour

So After one hour it increases by
$= \frac{2.5}{100} \times 506000 \\ = 12650$
Now bacteria is 5,06,000 + 12650
= 5,18,650

So After Two hours it increases By
$= \frac{2.5}{100} \times 518650 \\ = 12966.25$
Therefore after two hours bacteria increased by = 518650 + 12966.25
= 531616.25



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