Question

In a laboratory the count of bacteria in a certain experiment was increasing at the rate of 2.5%per hour. Find the bacteria at the end of 2hours if the count was initially 5,06,00

Answer 1

2.5% for 1 hour, therefore for 2hours 2.5% +2.5% = 5%
here,
5% of 50600= 5/100 × 50600
= 2530
now,
the count after 2hours = 2530+50600
= 75900

Therefore the count after 2hours is 75900