Question

In a laboratory the count of bacteria in a certain experiment was increasing at the rate of 2.5 % per hour find the bacteria at the end of 2 years if the count was initially 506000

Answer 1

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Here is your answer

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It is Given that:

Intial count of Bacteria (P) = 5,06,000

increasing Rate of Bacteria(R) = 2.5%,

Time = 2 hours

After 2 hours, number of bacteria,

Amount (A) = P(1+R/100)^n

A= 506000(1+2.5/100)^n

A= 506000(1+25/1000)²

A= 506000(1+1/40)²

A= 506000(41/40)²

A= 506000(41×41/40×40)

A= 506000×1681/ 1600

A=(5060 × 1681) /16

A= 316.25×1681

A= 5,31,616.25

Hence, the number of bacteria after two hours are 531616 (approximately).

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