Question

in a laboratory, the court Of bacteria in a certain experiment was increasing at the rate 2.5/per hour 2hours if the court was initially 5,06,000​

Answer 1

Please mark this answer as a brainliest answer

Answer 2

Answer:

531616

Step-by-step explanation:

We have, P0 = Original count of bacteria =506000,

Rate of increase =R=2.5% per hour,

Time =2 hours

∴ Bacteria count after 2 hours = P

P=P0(1+100R)T

=506000×(1+1002.5)2

=506000×100102.5×100102.5

=531616.25=531616 (approx)