Physics, asked by theekshnakkriya, 1 year ago

In a large building there are 15bulbs of 40 W,5 bulbs of 100 W,5 fans of 80W and a heater of 1KW. The voltage of the electric main is 220V. The minimum capacity of the main building will be

Answers

Answered by satish67
1
15*40=600w
5*100=500w
5*80=400w
1kw
total=2.5kw
I(current)=2.5k/220=11.37A
main capacity is 2.5kw/11.37A
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