Question

in a leap year the probability of 53 sundays is​

Answer 1

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HERE IS YOUR ANSWER!!!!!

considering a leap year

leap year contains 366 days

52 weeks plus two two extra days

52 weeks means definitely there are 52 sundays (this is true for all other days also).

if either of these two is sunday then we will have 53 sundays

these two days can be {mon, tue} or { tue , wed} or { wed , thurs} or {thurs , fri} or      { fri, sat} or { sat , sun} or {sun , mon} i.e total =7

out of these only two outcomes i.e { sat , sun} and {sun , mon} is having sunday with them .

so our desired probability is 2/7.

Answer 2

Answer:

We know that there are 366 days in a leap year = 52 weeks + 2 days.

These 2 days can be:

1. {Sun, mon}

2. {Mon, Tues}

3. {Tues, Wed}

4. {Wed, Thurs}

5. {Thurs, Fri}

6. {Fri, Sat}

7. {Sat, Sun}

n(s) = 7.

Now,

Out of these 7 outcomes, the favorable outcomes are 2.(Sun, mon),(Sat, Sun).

n(a) = 2.

Therefore the required probability p(A) = n(A)/n(S)

                                                                 = 2/7.